The base of a right pyramid is an equilateral triangle with side 8cm and the hieght of the pyramid is 24 root3 cm the volume in cm cube of the pyramid is
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Answer:
384cm³
Step-by-step explanation:
side of equilateral triangle=8cm
hight of pyramid=24√3
area of the base of right pyramid=√3/4s²
where s is side of triangle....
= √3/4×8×8
= √3×16
then , volume of pyramid= ⅓AH
where A is area of triangle
⅓×16√3×24√3
=16√3×8√3
= 128√9
=128×3 =. 384cm³
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