Question

The base of a right pyramid is an equilateral triangle with side 8cm and the hieght of the pyramid is 24 root3 cm the volume in cm cube of the pyramid is

Answer 1

Answer:

384cm³

Step-by-step explanation:

side of equilateral triangle=8cm

hight of pyramid=24√3

area of the base of right pyramid=√3/4s²

where s is side of triangle....

= √3/4×8×8

= √3×16

then , volume of pyramid= ⅓AH

where A is area of triangle

⅓×16√3×24√3

=16√3×8√3

= 128√9

=128×3 =. 384cm³