Question

The base of a right pyramid
is equilateral traingle of side
10√3 cm. If the total surface
are of the pyramid is 270√3
sq. cm. Its height is​

Answer 1

In the pyramid there are 3 triangular surfaces each with height(say h) and base with each side of equilateral triangle of 10√3 cm. Therefore total surface area = area of equilateral triangle + surface area of each triangle

√3/4 * 10√3 * 10√3 + 3 * 1/2 * 10√3 * h = 270√3

300√3/4 + 30√3*h/2 = 270√3

h = 12 hope it is helpful mark me as brainliest