the base of a right triangle is 4 cm and the hypotenuse is 5 cm find its perimeter
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Answered by
29
By RHS.
Hypotenuse²=base²+altitude²
→5²=4²+altitude²
→altitude²=25-16=9
→altitude=√9=3cm..
So perimeter of a triangle=Altitude+base+hypotenuse=3+4+5=12cm.
Hope it Helps...
Regards,
Leukonov.
Hypotenuse²=base²+altitude²
→5²=4²+altitude²
→altitude²=25-16=9
→altitude=√9=3cm..
So perimeter of a triangle=Altitude+base+hypotenuse=3+4+5=12cm.
Hope it Helps...
Regards,
Leukonov.
Answered by
15
By Pythagoras Theorem,
➡( base )² + ( height )² = ( hypotenuse )²
➡ ( 4 )² + ( height )² = ( 5 )²
➡ height = √{ 25 - 16 }
➡ height = √9
↪ height = 3 cm
Now we have all the three sides of a right angled triangle which were required to get the perimeter.
We know that perimeter = sum of all sides
So, Here
▶ Perimeter = base + height + hypotenuse
▶ Perimeter = 3 cm + 4 cm + 5 cm
⏩ Perimeter = 12 cm
Hence the perimeter of the Right - angled triangle will be 12 cm.
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➡( base )² + ( height )² = ( hypotenuse )²
➡ ( 4 )² + ( height )² = ( 5 )²
➡ height = √{ 25 - 16 }
➡ height = √9
↪ height = 3 cm
Now we have all the three sides of a right angled triangle which were required to get the perimeter.
We know that perimeter = sum of all sides
So, Here
▶ Perimeter = base + height + hypotenuse
▶ Perimeter = 3 cm + 4 cm + 5 cm
⏩ Perimeter = 12 cm
Hence the perimeter of the Right - angled triangle will be 12 cm.
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