Math, asked by Akanshnama2912, 1 year ago

The base of a tight angeled triangle measures 4 cm and its hypotuneous measures 5 cm. Find the areq of the triangle

Answers

Answered by Anonymous
0
height = 3

area = 1/2 × 3× 4
= 6
Answered by debtwenty12pe7hvl
0

Let the triangle have vertices A, B and C( Diagram in attachment )

AB = 48cm

CB = 50cm

AC =?

Since the triangle is a right angled triangle , the side AC can be found by using the PYTHAGORAS THEOREM

So,

(AB)² + (AC)² = (CB)²

(4)² + (AC)² = (5)²

(AC)² = (5)² - (4)²

(AC)² = 25 - 16

(AC)² = 9

AC = √9

AC = 3cm

since it is a right angled triangle ,in which AC is perpendicular to the base , it will be the height

So,

Base = 4cm

Height =3cm

Area of triangle = 1/2 × base × height

= 1/2 *4 *3

= 6cm²    Area of triangle  ANS

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