The base of a triangle field is three times it's altitude . if the cost of levelling the field at rupees 30.50 per sq. meter is rupees 7350 find its base and height
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Answer:
g
Step-by-step explanation:
When 11 is subtracted from 2 times
a number the result is 15 the number
is?
Answer:
We know the area of a triangle = x (base) x (altitude)
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = a
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metre
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50Given : 30.50 A = 7350
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50Given : 30.50 A = 7350 => A = 240.98 sq.metre
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50Given : 30.50 A = 7350 => A = 240.98 sq.metreTherefore,
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50Given : 30.50 A = 7350 => A = 240.98 sq.metreTherefore, => a = 12.67 metre
We know the area of a triangle = x (base) x (altitude)Let the altitude of the triangle = atherefore, base length = 3a=> area, A = x 3a x a=> sq.metrePrice of levelling the field of area A = A x 30.50Given : 30.50 A = 7350 => A = 240.98 sq.metreTherefore, => a = 12.67 metreHence, altitude length = 12.67 metre , and base length = 38.01 metre.
Step-by-step explanation: