Question

The base of a triangle is 15 cm height 12 cm find the height of another triangle of double the area have the base 20cm

Answer 1

$\Huge{\boxed{\red{\mathbb{ANSWER}}}}$

$\bold{Given\:that,}$

Base of $triangle_{1}$ = 15cm

Height of $triangle_{1}$ = 12cm

Base of $triangle_{2}$ = 20cm

$\bold{To\:find,}$

The height of $triangle_{2}$

Before finding area of $triangle_{2}$ we have to find the area of $triangle_{1}$.

Area of $triangle_{1} = \frac{1}{2} \times base \times height$

Area = \frac{1}{2} \times 15cm \times 12cm [/tex]

Area = \frac{1}{2} \times 180cm^2 [/tex]

Area = $90cm^2$

Now, in $triangle_{2}$ the area is doubled the area of $triangle_{1}$.

Area of $triangle_{2} = 90 \times 2$

Area of $triangle_{2} = 180cm^2$

Area = $\frac{1}{2} \times base \times height$
H
Area = $\frac{1}{2} \times 20cm \times h.$

Area = $\frac{1}{2} \times 20h$

$180cm^2 = 10h$

$\frac{180cm^2}{10m} = h$

18cm = h