Question

The base of a triangle is 4 cm longer than its altitude if the area of the triangle is 48 sq cm then find its base and altitude

Answer 1

Answer:

Let altitude be x cm

Base = x + 4 cm

Area = 1/2 × base × height

48 = 1/2 ×x × (x+4)

48×2 = x^2 + 4x

0 = x^2 +4x -96

0 = x^2 +12x - 8x - 96

0 = x(x + 12) -8(x +12)

0 = (x+12)(x-8)

x - 8 = 0

x = 8

x +4 = 12