The base of a triangle is 4 cm longer than its altitude if the area of the triangle is 48 sq cm then find its base and altitude
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Let altitude be x cm
Base = x + 4 cm
Area = 1/2 × base × height
48 = 1/2 ×x × (x+4)
48×2 = x^2 + 4x
0 = x^2 +4x -96
0 = x^2 +12x - 8x - 96
0 = x(x + 12) -8(x +12)
0 = (x+12)(x-8)
x - 8 = 0
x = 8
x +4 = 12
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