Question

The base of a triangle is 4 times its height and its area is 50 cm square. The length of its base is

Answer 1

Given ,

base of a triangle = 4 times of its height

area of triangle = 50 $cm^{2}$

To find,

Length of its base

Solution,

Area of triangle = $\frac{1}{2} bh$

Let the height of triangle be h

Then the base of a triangle = 4h

So , $50cm^{2} = \frac{1}{2}(4h)(h)$

$50cm^{2} = 2h(h)$

$25 cm^{2} = h^{2}$

Therefore , h = 5cm

Base = 4h = 4(5) = 20cm

Hence,the base of the triangle is 20 cm.

Answer 2

Answer:

Area of triangle = \frac{1}{2} bh

2

1

bh

Let the height of triangle be h

Then the base of a triangle = 4h

So , 50cm^{2} = \frac{1}{2}(4h)(h)50cm

2

=

2

1

(4h)(h)

50cm^{2} = 2h(h)50cm

2

=2h(h)

25 cm^{2} = h^{2}25cm

2

=h

2

Therefore , h = 5cm

Base = 4h = 4(5) = 20cm

Hence,the base of the triangle is 20 cm.