Question

The base of a triangle is 40 cm longer than its altitude.If the area of the triangle is 48sq.cm then find its altitude& base

Answer 1

Answer:

b=42

h=2

Step-by-step explanation:

let 'b' be base and 'h' be altitude

Area=1/2× base× altitude

48=1/2×(40+h)h

48×2=40h+h²

96=40h+h²

rearranging im quadratic form:

h²+40h-96=0

using formulla

h=(-b±√b²-4ac)/2a

h=(-40±(√40²-4×1×(-96))/2

h=(-40±44)/2

h=2,-44

height cannot b negative

ao altitide =2

and base=40+2=42