Question

The base of a triangle is 4cm greater than its altitude if it's area is 48cm find the height​

Answer 1

1/2 * bh=A

b=h+4

1/2 * h(h+4)=48

1/2(h^2+4h)=48

h^2+4h=96

h^2+4h-96=0

(h-8)(h+12)=0

h=8, b=12

By edjones

Answer 2

꧁SOLUTION ꧂

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Given

• The area of triangle=48cm²

LET

• The altitude of triangle be X
• The base of triangle be X+4

According to the above information

Area of triangle

$= > \frac{1}{2} \times b \times a = 48 \\ \\ = > \frac{1}{2} \times (x + 4) \times x = 48 \\ \\ = > {x}^{2} + 4x = 96 \\ \\ = > {x}^{2} + 4x - 96 = 0 \\ \\ = > {x}^{2} + 12x - 8x - 96 = 0 \\ \\ = > x(x + 12) - 8(x + 12) = 0 \\ \\ = > (x - 8)(x + 12) = 0 \\ \\ = > x = (8 )\: ( - 12)$

• negative value can't be kept
• so, value of X=8cm

Dimension of triangle

• base=12cm
• altitude=8cm