Question

the base of a triangle is 4cm longer than its altitude. if the area of the triangle is 48sq.cm then find its base and altitude ​

Answer 1

Answer:

Base of a triangle is 4 cm longer than its altitude.

Area of triangle =48 cm  

2

 

Let base of triangle =b

Altitude =b−4

Area =  

2

1

​  

×b×h=48

2

1

​  

×b×(b−4)=48

b  

2

−4b−96=0

(b−12)(b+8)=0

But, base cannot be negative

So, base =12 cm

Altitude=12−4=8 cm.

Step-by-step explanation: