Question

the base of a triangle is 9 cm and height is 5 centimetre the base of another triangle is 10 cm 10 cm and height is 6 cm find the ratio of areas of these triangles​

Answer 1

Let, 
The triangle having 9 units as base and 5 units as height is ∆ ABC
the triangle having 10 units as base and 6 units as height is ∆ PQR

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Now, 

Area of ∆ ABC = (base × height)/2

Area of ∆ ABC =(9×5)/2

Area of ∆ ABC = 45/2 = 22.5 unit²

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Area of ∆ PQR = (10×6)/2

Area of ∆ PQR = 10×3=30 unit²

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Ratio = 22.5 : 30

Ratio= 225:300

Ratio = 3:4

I hope this will help you 

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4