Question

The base of a triangle is 9 cm and height is 5 cm . The base of another triangle is 10 cm and height is 6 cm. Find the ratio of areas of these triangle.

Answer 1

Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.
In ∆ABC,
Base of ∆ABC is BC = 9cm
Altitude of ∆ABC is AE = 5cm

In ∆PQR,
Base is QR = 10cm
Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-




Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4



Hope it helps..

Answer 2

Answer :

The ratio of the areas of the triangles is 3 : 4

Step-by-step explanation :

Find the area of first triangle :

Base of triangle = 9cm

Height of triangle = 5cm

Area of triangle = 1 / 2 × base × height

⇒ 1 / 2 × 9 × 5

⇒ 45 / 2

Find the area of second triangle :

Base of triangle = 10 cm

Height of triangle = 6 cm

Area of triangle = 1 / 2 × base × height

⇒ 1 / 2 × 10 × 6

⇒ 30 cm

Find the ratio of the areas of both the triangles ;

Ratio = Area of first Δ / Area of 2nd Δ

Ratio = 45 / 2 × 1 / 30

Ratio = 3 / 4

Ratio = 3 : 4

Hence, the required ratio is 3 : 4