Question

The base of a triangle is 9cm & its height is 5cm the base of another triangle is 10cm & height is 6cm find the ratio of area of those triangle plz give ans fast it's urgent....

Answer 1

Here is the step-by-step explanation of your query:-

Given:-

Base of 1st ∆ = 9cm

Height of 1st ∆ = 5cm

Base of 2nd ∆ = 10cm

Height of 2nd ∆ = 6cm

Therefore,

Area of 1st ∆ = 1/2 × 9 ×5

= 45/2cm^2

Area of 2nd ∆ = 1/2 × 10 × 6

= 30cm^2

Ratio,

Area of 1st ∆ 45/2

———————— = ————

Area of 2nd ∆ 30

Area of 1st ∆ 3

-------------------- = --------

Area of 2nd ∆ 4

Area of 1st : Area of 2nd = 3:4 Ans

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(Answer By :- Anshul Kumar )

Answer 2

Area of triangle=b×h
A(PQR)=9×5
=10×6
A(PQR)=3/4