The base of a triangle triangle is twice as long as a side of a square then areas are equal then the ratio of altitude of triangle to the base to the side of square is??
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Let h, b be the height and base of the triangle.
Let a be the side of square.
Given b = 2a
Areas are same.
2
1
bh=a
2
2
1
(2a)h=a
2
∴h=a
∴h:a=1:1⟹
a
h
=1
Ratio of the altitude of the triangle to the side of the square = 1
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