Question

The base of a triangular field is 840 m and its altitude is 550 m. Find the cost of reaping the field at the
rate of 2500 per hectare. (Hint: 1 hectare = 10,000 m²)​

Answer 1

Answer:

area= 1/2 x base x height

A=1/2 ×550m×840m

A = 550m×420m

A=231000m^2  

Converting m^2 into hectare= 231000/10000

= 23.1 hectare

Cost of reaping=23.1×2500= Rs 57750

Hope it helps!!

Answer 2

$\underline{ \underline{ { \huge{ \mathtt{Q}}} \sf {UESTION - }}}$

The base of a triangular field is 840 m and its altitude is 550 m. Find the cost of reaping the field at the rate of 2500 per hectare.

$\underline{ \underline{{ \huge{ \mathtt{A}}} \sf {NSWER -}}}$

we know that,

$\boxed{ \gray{ \sf{Area \: of \: triangle = \frac{1}{2} \times base \times height}}}$

$\sf \therefore \: Area \: of \: triangular \: field = \frac{1}{ \cancel2} \times 840 \times \cancel{550} \: ^{275} \\ \\ \sf \implies \: 231000 \: {m}^{2} \: to \: hectare \\ \sf \implies \: 1 \: {m}^{2} = \frac{1}{10000} \: hectare \\ \\ \sf \implies \: \frac{231 \cancel0 \cancel0 \cancel0}{10 \cancel0 \cancel0 \cancel0} \\ \\ \sf \implies \: 23.1 \: hectare$

so,

$\sf \: Cost \: of \: reaping \:the \: field = Area \: of \: triangular \: field × rate \\ \sf \implies \: 23.1 \times 2500 \\ \boxed{ \red{ \sf \implies \: ₹ \: 57750 \: \: \: ans..}}$

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@MissSolitary✌️

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