Question

the base of a triangular field is 840m amd its altitude is 550m.find the cost of reaping the field at the rate of ₹2500 per hectare

Answer 1

☆Hello friend☆

$area = \frac{1}{2} \times base \times height$
A=1/2 ×550m×840m
A = 550m×420m
A=231000m^2

Converting m^2 into hectare= 231000/10000
= 23.1 hectare
Cost of reaping=23.1×2500= Rs 57750

Hope it helps

☺☺☺

Answer 2

Given is the base, altitude, and reaping rate of a triangular field, Find the cost of reaping the field.

Explanation:

• Let there be a triangle having base length 'b' and altitude length 'h'.
• Then the area of said triangle is given by, $A=\frac{1}{2} bh$  
• Hence here for the triangular field we have, $b=840\ m,\ \ \ \ h=550\ m$
• Therefore the area of the given field is,
•                  $->A=\frac{1}{2} (840)(550)\\->A=231000\ m^2$  
• Now in order to calculate the reaping cost we need to convert the given area from square meters to hectares,
•                  $->1\ m^2=0.0001\ ha\\->231000\ m^2=(231000)0.0001\ ha\\->A=23.1\ ha$  
• The rate of reaping the field per hectare is, $r=Rs.\ 2500/ha$
• Hence the cost of reaping the whole field is,
•                 $->C=Ar\\->C=23.1(2500)\\->C=Rs.\ 57750$  
• The cost of reaping the whole triangular field will be ₹$57750$.