Math, asked by RidhimaChhavi, 1 year ago

the base of a triangular field is three times its altitude. if the cost of cultivating the field at Rupee 280 per hectare is Rs 3780, find its base and altitude

Answers

Answered by rishabhranjanishwar1
39
Let height be x.
Base be 3x.
Area=3780/280=13.5hectare=135000m
3x×x/2=135000
x=300
height= 300m
base= 900m
Answered by wifilethbridge
20

Its base and altitude are 900 m and 300 m respectively.

Step-by-step explanation:

Let the altitude of triangular field be x

We are given that the base of a triangular field is three times its altitude.

So, Base = 3x

Area of triangle =\frac{1}{2} \times base \times Height=\frac{1}{2} \times 3x \times x

The cost of cultivating the field at Rupee 280 per hectare is Rs 3780

Area of field =\frac{3780}{280}=13.5 hectare

1 hectare = 10000 sq.m.

13.5 hectare = 13.5 \times  10000 =135000 sq.m.

So, \frac{1}{2} \times 3x \times x = 135000

x^2= \frac{135000 \times 2}{3}

x = \sqrt{\frac{135000 \times 2}{3}}

x =300

Base = 3x =3(300)=900 m

Height = 300 m

Hence its base and altitude are 900 m and 300 m respectively.

#Learn more:

The base of a triangular field is three times its altitude the cost of cultivating the field at 24.60 per hectare is 332.10 find its base and height​

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