Question

The base of a triangular field is three times its height and it's area is 1350 m2. Find the base and height of a field​

Answer 1

circumference of the base = 2πr = 88 cm.

2πr = 88

r = 88*7/2*44

r = 14 cm.

T.s.a = 2π r(r+h)

6512= 2*22/7*14(14+h)

6512= 88(14+h)

6512= 1232+88h

6512-1232=88h

5280 = 88h

h = 5280/88

h = 60 cm

vol. of cylinder = π*r^2*h

= 22/7*(14)^2*60

= 22/7*196*60

= 36960 cm^2

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