the base of a triangular field is three times its height.If the xost of cultivating the field at RS. 36 per hectare is RS. 486,find its base and height (1 hectare = 10000 m²).
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Answered by
166
heya,
area of triangle = 1/2×base×height.
1/2*x*3x
= 3/2x²
1 hectare = 10,000 sq. meter
the rate of cultivating the field = rs. 36
total cost = rs. 486.
total cost = area of the triangular field × rs. 36
3/2x² × 36/10,000 = 486.
x² =
x² = 90000 m²
x = 300 m
height of the triangular field = x = 300 m
base of the triangle field = 3x = 3*300 = 900m
thank you.
area of triangle = 1/2×base×height.
1/2*x*3x
= 3/2x²
1 hectare = 10,000 sq. meter
the rate of cultivating the field = rs. 36
total cost = rs. 486.
total cost = area of the triangular field × rs. 36
3/2x² × 36/10,000 = 486.
x² =
x² = 90000 m²
x = 300 m
height of the triangular field = x = 300 m
base of the triangle field = 3x = 3*300 = 900m
thank you.
nikhilkumar4:
welcome
Answered by
84
Let the altitude of the triangle be x.
Then the base of the triangular field is 3x.
We know that Area of the triangle = 1/2 * b * h
= 1/2 * 3x * x
= 3x^2/2.
Given that the cost of cultivating the field at 36 per hectare = 36 * 3x^2/2
= 54x^2/2.
54x^2 = 486
x^2 = 486/54
x^2 = 9 * 10000
x = 300
if the altitude is 300 then the base is 3 * 300 = 900.
Therefore the base = 900m.
the height = 300m.
Hope this helps!
Then the base of the triangular field is 3x.
We know that Area of the triangle = 1/2 * b * h
= 1/2 * 3x * x
= 3x^2/2.
Given that the cost of cultivating the field at 36 per hectare = 36 * 3x^2/2
= 54x^2/2.
54x^2 = 486
x^2 = 486/54
x^2 = 9 * 10000
x = 300
if the altitude is 300 then the base is 3 * 300 = 900.
Therefore the base = 900m.
the height = 300m.
Hope this helps!
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