the base of a triangular field is three times of its altitude. If the cost of levelling the field at rupees 25 per hectare is rupees 33 7.50, find its base and corresponding altitude
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Rate of levelling=₹25 / hectare
total cost of levelling =337.50
land in hectare=total cost /rate
= 337.25/25
= 13.49 hectare
as we know that 1 hectare is equal to10000 m²
so area of field = land in hectare x. 10000
= 13.49 x 10000
= 134900 m²
let altitude of field be @
then base will be 3@
area of triangle = 1/2 base x hight
134900= 1/2 x 3@ x @
134900 x 2 = 3 @²
134900 x 2 / 3 = @²
89,933.34 = @²
@ = 300 (approx)
altitude is 300 m
total cost of levelling =337.50
land in hectare=total cost /rate
= 337.25/25
= 13.49 hectare
as we know that 1 hectare is equal to10000 m²
so area of field = land in hectare x. 10000
= 13.49 x 10000
= 134900 m²
let altitude of field be @
then base will be 3@
area of triangle = 1/2 base x hight
134900= 1/2 x 3@ x @
134900 x 2 = 3 @²
134900 x 2 / 3 = @²
89,933.34 = @²
@ = 300 (approx)
altitude is 300 m
Answered by
1
Answer:
let the altitude of the triangle be x
Hence base = 3x
Area of triangle = (1/2) × base × height
= (1/2) × (x) × (3x) = 3x^2/2
Cost of sowing the field at rs 25 per hectare = 25 × 3x^2/2 = 75x^2/2
Therefore, 75x^2/2= 3375/10
=>x=3
Base = 3(3) = 9
Hence base is 9 and altitude is 3.
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