Question

THE BASE OF A TRIANGULAR REGION IS THREE TIMES ITS ALTITUDE.IF THE AREA IS 27sq.m, find the base and altitude​

Answer 1

Answer:

H = 27/2 and B = 51/2

Step-by-step explanation:

Area=27 sq.m

Given: B = 3H

Area = 1/2 x B x H 1/2

27 = (1/2)(3H)(H)

27 = (1/2)(4H)

4H=54

H = 27/4  

 substitute in B = 3H

B = 51/2

Answer 2

Answer:

Step-by-step explanation:

Let the altitude be x

Therefore, Base is 3x

Area=27m²                                                         (given)

Area of Triangle = 1/2 × base × height

⇒ 1/2 × x × 3x = 27

3x²=54

x²=18

∴x = √18

⇒3√2

∴Altitude =3√2

Base = 9√2