The base of a wooden box measures 24cm x 30cm . It is placed on a bed. If the weight of the box is 216N , what is the pressure exerted by the box on the bed
Answers
Answer:
- 3000 N/m² is the required pressure .
Explanation:
According to the Question
It is given that,
- Dimension of box = 24cm × 30cm
- Force ,F = 216N
we have to calculate the pressure exerted by the box on the bed .
As we know that Pressure is defined as the Force acting per unit area .
Firstly we calculate the base area of box.
Base area of box
→ Area = 24×30
→ Area = 720 cm²
changing into m²
→ Area = 720/10000 = 0.072 m²
Now, calculating the pressure exerted by the box on the road .
- Pressure = Force/Area
substituting the value we get
⇢Pressure = 216/0.072
⇢Pressure = 216000/72
⇢Pressure = 3000 N/m²
- Hence, the pressure exerted by box on the road is 3000 Pa.
Explanation:
Answer:
3000 N/m² is the required pressure .
Explanation:
According to the Question
It is given that,
Dimension of box = 24cm × 30cm
Force ,F = 216N
we have to calculate the pressure exerted by the box on the bed .
As we know that Pressure is defined as the Force acting per unit area .
Firstly we calculate the base area of box.
Base area of box
→ Area = 24×30
→ Area = 720 cm²
changing into m²
→ Area = 720/10000 = 0.072 m²
Now, calculating the pressure exerted by the box on the road .
Pressure = Force/Area
substituting the value we get
⇢Pressure = 216/0.072
⇢Pressure = 216000/72
⇢Pressure = 3000 N/m²
Hence, the pressure exerted by box on the road is 3000 Pa.