Question

The base of an asosceles triangle is 4/3 cm.
The perimenter of the triangle is 42/15 cm.what
is the length of either of the remaining equal
sides?
​

Answer 1

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The base of an isosceles triangle is $\red{\frac{4}{3}}$ cm

The perimeter of the isosceles triangle is $\green{\frac{42}{15}}$ cm

$\huge{\boxed{\sf{\blue{To}\ \green{find:}}}}$

The length of the equal sides of the isosceles triangle

Some properties of an isosceles triangle

• It has two equal sides and two equal angles.

Now,

Let the sides of the two equal sides be x cm

Now.

• Perimeter of isosceles triangle = Sum of all sides

⇒ x + x + $\frac{4}{3}$ = $\frac{42}{15}$

⇒ 2x + $\frac{4}{3}$ =$\frac{42}{15}$

⇒ 2x = $\frac{42}{15}$ - $\frac{4}{3}$

⇒ 2x = $\frac{42 - 20}{15}$

⇒ 2x = $\frac{22}{15}$

⇒ x = $\frac{22}{15} \div 2$

⇒ x = $\frac{22}{15} \times \frac{1}{2}$

⇒ x = $\frac{11}{15}$

Thus,

The other two equal sides are x cm = $\frac{11}{15}$

Answer 2

Answer:

Correct Question:

The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 42/15 cm. What is the length of either of the remaining equal sides?

Solution:

We know that in an isosceles triangle both sides are equal.

Let the length of the two equal sides of the triangle be 'x' cm. Then,

$\frac{4}{3} + x + x = \frac{42}{15} \\ \\ = > \frac{4}{3} + 2x = \frac{42}{15} \\ \\ = > 2x = \frac{42}{15} - \frac{4}{3} \\ \\ = > 2x = \frac{22}{15} \\ \\ = > x = \frac{22}{15} \div 2 \\ \\ = > x = \frac{22}{15} \times \frac{1}{2} \\ \\ = \frac{11}{15}$

Since x = 11/5 cm, length of both the sides of the triangle will be 11/5 cm.