Question

The base of an equilateral triangle ABC lies on the y-axis. The coordinates of the point C is (0, – 3). If origin is the midpoint of BC, then the coordinates of B are​

Answer 1

Step-by-step explanation:

O is the mid-point of the base BC.

Therefore, coordinates of point B are (0,3).

So, BC = 6 units

Let the coordinates of point A be (x,0).

Using distance formula,

AB=

(0−x)

2

+(3−0)

2

=

x

2

+9

BC=

(0−0)

2

+(−3−3)

2

=

36

Also, AB = BC

x

2

+9

=

36

x

2

+9=36

x

2

=27

x=±3

3

Coordinates of A = (3

3

,0).

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