Question

the base of an equilateral triangle is 8 cm and one of its equal side is 5 cm then the area of triangle is​

Answer 1

#answerwithquality #BAL

Answer 2

The area  of triangle=$12cm^2$

Step-by-step explanation:

Base of isosceles  triangle, a=8cm

Side of isosceles triangle are

b=5 cm=c

Semi-perimeter of triangle,s=$\frac{a+b+c}{2}=\frac{8+5+5}{2}=9cm$

Area of triangle by Heron's formula

$=\sqrt{s(s-a)(s-b)(s-c)}$

By using the formula

Area of given triangle =$\sqrt{9(9-8)(9-5)(9-5)}$

Area of given triangle=$\sqrt{9\times 4\times 4}$

Area of given triangle=$12cm^2$

Hence, the area  of triangle=$12cm^2$

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