Question

the base of an equilateral triangle is 8 cm and one of its equal side is 5 cm then the area of triangle is​

Answer 1

12 cm² is area of an isosceles triangle whose base = 8 cm & one of equal sides = 5 cm

Step-by-step explanation:

the base of an equilateral triangle is 8 cm and one of its equal side is 5 cm

Mistake in data

if it is an equilateral triangle then either all sides would be equal either 8 cm or 5 cm

Area pf Equilateral Triangle = (√3 / 4)side²

it should be an isosceles triangle

with one side = 8 cm & other teo sides = 5 cm

s = (8 + 5 + 5)/2 = 9

Area of Triangle = √ 9(9-8)(9-5)(9-5)

= √9 * 1 * 4 * 4

= 3 * 4

= 12

12 cm² is area of an isosceles triangle whose base = 8 cm & one of equal sides = 5 cm

Learn more:

Find the area of triangle having vertices at (8,1) ,(1,-4),(4,-5)

https://brainly.in/question/12350448

In the figure area of triangle abd is 10 sq. cm and area of triangle adc

https://brainly.in/question/12511861