The base of an iscoceles triangle is 12 cm and it’s perimeter is 32 cm. Find the Area
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Let the equal sides of the isosceles triangle be=a and the base be=b.
Given b=12cm
Perimeter of triangle=Sum of all sides=a+a+b=32(Given)
==>2a+12=32
2a=32-12(Transposing)
2a=20
a=20/2
a=10cm
Since the height of the triangle divides it into 2 right angled triangles
a^2=h^2+(b/2)^2
==>10^2=h^2+6^2
100=h^2+36
100-36=h^2
64=h^2
h=8cm(Root of 64)
Area of triangle=1/2 x base x height
==>1/2x12x8
==>48cm square
Given b=12cm
Perimeter of triangle=Sum of all sides=a+a+b=32(Given)
==>2a+12=32
2a=32-12(Transposing)
2a=20
a=20/2
a=10cm
Since the height of the triangle divides it into 2 right angled triangles
a^2=h^2+(b/2)^2
==>10^2=h^2+6^2
100=h^2+36
100-36=h^2
64=h^2
h=8cm(Root of 64)
Area of triangle=1/2 x base x height
==>1/2x12x8
==>48cm square
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