Question

the base of an isoceles triangle is 16 CM and it's perimeter is 56cm.Find the area of the triangle​

Answer 1

32 × root 21 answer

Hope it helps

Answer 2

Answer:

12√65 cm² or 96.744 cm²

Step-by-step explanation:

Let the equal sides of the isosceles triangle be x

So, 16 + x + x = 56

16 + 2x = 56

2x = 40

x = 20

So the sides are:

16cm

20 cm

20 cm

According to Heron's formula, the area of a triangle is given by:

$\sqrt{s(s-a)(s-b)(s-c)}$ where s is semi perimeter and a, b and c measures of the sides of the triangle

so, s = $\frac{56}{2}$ = 26

$\sqrt{s(s-a)(s-b)(s-c)} \\\\=\sqrt{26(26-16)(26-20)(26-20)} \\\\=\sqrt{26(10)(6)(6)} \\\\=\sqrt{(2)(13)(2)(5)(6)(6)} \\\\=(2)(6)\sqrt{65} \\\\=12\sqrt{65} cm^2\\\\=(12)(8.062)\\\\=96.744 cm^2$