Question

the base of an isoceles triangle is 4/3 cm .the perimeter of the triangle is 4 2/15 cm . what is the length of either of the remaining equal sides ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let each equal side of an isosceles triangle ABC be x cm.

Then, its perimeter =AB+BC+CA=(x+

3

4

+x) cm =(2x+

3

4

) cm

But it is given that the perimeter of the triangle =4

15

2

cm =

15

62

cm

Therefore, 2x+

3

4

=

15

62

⇒30x+20=62 ...[On multiplying both sides by 15]

⇒30x=62−20

⇒30x=42

⇒x=

30

42

=

5

7

=1

5

2

Thus, each equal side of the isosceles traingle is of 1

5

2

cm.