Question

the base of an isoceles triangle is 48cm and one of it's equal side is 30cm . Find the area of the triangle

Answer 1

Here AD is the perpendicular, we can see that triangle ABD is congruent to triangle ACD by RHS. Therefore, DC =48/2=24 and AC is given 30. Using Pythagoras Theorem we get AD=18. Now we can use the formula to find the area.
$a = \frac{1}{2} \times 48 \times 18 \\ a = 48 \times 9 = 424$

Answer 2

heya dude...
here is ur answer...!!!!!

one of the sides of isosceles triangle=30 cm
base of the triangle=48 cm
the height of the triangle=18 cm
area of the triangle=1/2 X base X height
                            =1/2 X 48 X 18
                            =1/2 X 48 X 18
                            =24X 18
                            =432 cm2
ANSWER is 432 cm2

thanks....!