Question

the base of an isocelese triangle is 4/5 cm the perimeter of the triangle is 5 integer 3/13 cm what is the length of either of the remaining equal sides​

Answer 1

Answer:

Let the length of equal sides be x cm.

Perimeter = x cm + x cm + Base = 4 2/15

2x + 4/3 = 62/15

On transposing 4/3 to R.H.S, we obtain

2x = 62/15 - 4/3

2x = 62 - 4 x 5/15 = 62 - 20/15

2x = 42/15

On dividing both sides by 2, we obtain

2x/2 = 42/15 x1/2

x = 7/5 = 1 2/5

Therefore, the length of equal sides is 1 2/5 c

HOPE THIS HELPS YOU BETTER

PLZ MARK ME AS BRAINLIEST ♡