Question

the base of an isosceles as 4/3 CM. the perimeter of the triangle is 4/2/15 .what is the length of the remaining equal sides?​

Answer 1

Answer:

1 2/3 cm [or] 7/5 cm [or] 1.4 cm

Step-by-step explanation:

Perimeter

= 4 2/15 = (60+2)/15 = 62/15 cm

also perimeter= AB+BC+AC   .....[let AB=AC=x]

62/15= 2x+4/3

2x= (62/15) - (4/3)    .....[ (4*5)/(3*5) = 20/15 ]

2x= (62-20)/15 = 42/15

x = 42/ (15*2) = 42/30 = 21/15 = 7/5

x= 1²/₅ cm

Hope it helps u!!