Question

the base of an isosceles right angled triangle is 25 cm then what is its area?

Answer 1

Step-by-step explanation:

consider triangle ABC , angle B=90°,where AB=25cm,BC=25cm and CA=X cm

By Pythagoras theorem,

AB^2+BC^2=AC^2

(25)^2+(25)^2=X^2

625+625=X^2

1250=X^2

√1250=X

√5×5×5×5×2=X

25√2=X

therefore,X=AC=25√2 cm