Question

The base of an isosceles triangle 48cm and one of its equal side 30cm find the areaof the triangle

Answer 1

a = 30 cm , b= 48 cm
$ar \: of \: isosceles \: triangle = \frac{1}{4} b \sqrt{4 {a}^{2} - {b}^{2} } \\ \: \: \: \: \: \: \: = \frac{1}{4} 48 \sqrt{4 {(30) }^{2} - {(48)}^{2} } \\ \: \: \: \: \: \: \: = 12 \sqrt{4 \times 900 - 2304} \\ \: \: \: \: \: \: \: = 12 \sqrt{3600 - 2304} \\ \: \: \: \: \: \: \: = 12 \sqrt{1296} = 12 \times 36 = 432 {cm}^{2}$