The base of an isosceles triangle 5/8cm the perimeter of the triangle is 41/12 what is the length of either of the remaining equal side
Answers
Answered by
7
Base=4/3cm
Let the equal sides be x.
Perimeter=S1+S2+S3
62/15=x+x+4/3
62/15=2x+4/3
62/15-4/3=2x
(62-20)/15=2x
42/15/2=x
42/15×1/2=x
21/15=x
7/5=x
Thus,
Two equal sides = x = 7/5cm
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Answered by
8
Answer:
67/48cm
Step-by-step explanation:
Length = ?
Base = 5/8cm
Side = ?
Perimeter = 41/12cm
Lets the equal sides be x
=> P = S1+S2+S3
=> 41/12cm = x+x+5/8cm
=> 41/12cm - 58cm = 2x(transposing method)
=> LCM = 24
=> 41/12 both multiplied to 2cm-5/8 Both multiplied to 3 = 2x
=> 82/24cm - 15/25cm = 2x
=> 82-15/24 = 2x
=> 67/24cm = 2x
=> x = 67/24cm / 2x
=> x= 67/24 multiplied to 1/2x
=> 67/48 cm = x
Thus,
2 equal sides = x = 67/48cm
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