Question

The base of an isosceles triangle 5/8cm the perimeter of the triangle is 41/12 what is the length of either of the remaining equal side

Answer 1

Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)/15=2x

42/15/2=x

42/15×1/2=x

21/15=x

7/5=x

Thus,

Two equal sides = x = 7/5cm

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Answer 2

Answer:

67/48cm

Step-by-step explanation:

Length = ?

Base = 5/8cm

Side = ?

Perimeter = 41/12cm

Lets the equal sides be x

=> P = S1+S2+S3

=> 41/12cm = x+x+5/8cm

=> 41/12cm - 58cm = 2x(transposing method)

=> LCM = 24

=> 41/12 both multiplied to 2cm-5/8 Both multiplied to 3 = 2x

=> 82/24cm - 15/25cm = 2x

=> 82-15/24  = 2x

=> 67/24cm = 2x

=> x = 67/24cm / 2x

=> x= 67/24 multiplied to 1/2x

=> 67/48 cm = x

Thus,

        2 equal sides = x = 67/48cm