Math, asked by agrim18mt, 8 months ago

The base of an isosceles triangle ABC is 24 cm and the two equal sides are 37 cm each. Find the altitude AD of the triangle.

Answers

Answered by adarshmishra2004
12

Answer:I hope this will help u...

Step-by-step explanation:

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Answered by haridasan85
15

Answer:

ISOSCELES TRIANGLE

a=equal sides

b=base

Area = b/4V4a^2-b^2. OR use vs (s-a)(s-b)(s-c), (s=a+b+c)/2

= 24/4v4x37^2-24^2

= 6v4x1369-576

= 6v 5476-576

= 6v 4900

= 6x70=420cm2

Area = 1/2 bh=420

bh=840

b = 24

h = 840/24 =35cm Ans

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