The base of an isosceles triangle ABC is 24 cm and the two equal sides are 37 cm each. Find the altitude AD of the triangle.
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Answer:
ISOSCELES TRIANGLE
a=equal sides
b=base
Area = b/4V4a^2-b^2. OR use vs (s-a)(s-b)(s-c), (s=a+b+c)/2
= 24/4v4x37^2-24^2
= 6v4x1369-576
= 6v 5476-576
= 6v 4900
= 6x70=420cm2
Area = 1/2 bh=420
bh=840
b = 24
h = 840/24 =35cm Ans
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