Question

the base of an isosceles triangle is 10 cm and one of its equal side is 13 cm find its area using heron's formula

Answer 1

SP=18(P/2)
underroot=18(8)(5)(5)
5760
Answer is-75.9 approx

Answer 2

s=13+13+10/2=18

area=
$\sqrt{18(18 - 10)(18 - 13)(18 - 13) }$
=
$\sqrt{18 \times 8 \times 5 \times 5}$
= 60 cm^2