the base of an isosceles triangle is 12 centimetres and the same sides are unknown, its perimeter is 32 CM find the area of this triangle using heron's formula.
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Answer:
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Step-by-step explanation:
Answer
Let the congruent sides of the isosceles triangle =a and the base =b.
Given, b=12cm
Perimeter of the triangle =Sum of all sides = a + a + b =32
⇒2a+12=32
On solving, a =10cm
Since the height of the triangle, divides it into two right angled triangles,
a
2
=h
2
+(
2
b
)
2
⇒10
2
=h
2
+6
2
h
2
=100−36=64
h=
64
=8 cm
Area of triangle =
2
1
×base×height=
2
1
×12×8=48 sq cm
Answered by
0
Answer:
Let the congruent sides of the isosceles triangle =a and the base =b.
Given, b=12cm
Perimeter of the triangle =Sum of all sides = a + a + b =32
⇒2a+12=32
On solving, a =10cm
Since the height of the triangle, divides it into two right angled triangles,
a
2
=h
2
+(
2
b
)
2
⇒10
2
=h
2
+6
2
h
2
=100−36=64
h=
64
=8 cm
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