The base of an isosceles triangle is 12 cm and it's perimeter is 84 cm find the area of the triangle
Please answer fast as I have my exam tomorrow
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Step-by-step explanation:
Exercise 2.2 the base of an isosceles triangle is 4/3 cm. the perimeter of the triangle is 62/15 cm.
Answered by
2
Step-by-step explanation:
Let the congruent sides of the isosceles triangle =a and the base =b.
Given, b=12cm
Perimeter of the triangle =Sum of all sides
= a + a + b =32
⇒2a+12=32
On solving, a =10cm
Since the height of the triangle, divides it into two right angled triangles,
a2=h2+(2b)2⇒102=h2+62
h2=100−36=64
h=64=8 cm
Area of triangle =21×base×height
=21×12×8
=48 sq cm
hope it helps you ❤
all the best for your exam dear.
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