Question

The base of an isosceles triangle is 12 cm and it's perimeter is 32 cm find its area​

Answer 1

Solution

Given :-

• The base of an isosceles triangle is 12 cm.
• Its perimeter is 32.

Find :-

• Area of isosceles triangle

Explanation

We Know,

★ Perimeter of isosceles triangle = 2a + b

Where,

• a = equal side of isosceles
• b = base of isosceles

★ Area of isosceles = √[(a² - b²/4)]

Now,

==> perimeter of isosceles = 2a + 12

==> 32 = 2a + 12

==> 2a = 32 - 12

==> 2a = 20

==> a = 20/2

==> a = 10

Since,

• Equal side of triangle be a = 10 cm

Now,

==> Area of isosceles = √[(10² - 12²/4)]

==> Area of isosceles = √[(100 - 144/4)]

==> Area of isosceles = √[100 - 36]

==> Area of isosceles = √64

==> Area of isosceles = 8 cm²

Hence

• Area of isosceles triangle will be = 8

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