Question

The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. find the area.​

Answer 1

Answer:

Let x be the equal side.

==>Perimeter:2x+12=32.

x=10cm.

Height of the base=8 (by solving using Pythagorean theorem).

Area of triangle=1/2*b*h.

Area of triangle =1/2*12*8.

Area of triangle=48cm^2.

Answer 2

isoscelestriangle:

Base=12cm

sum of other 2 Sides=32-12=20

equal sides=20/2=10cm each

sides of this triangle 12, 10, 10

semiperimeter=(12+10+10)/2 = 32/2=l6

Area =vs (s-a)(s-b)(s-c)

=v16 (16-12) (16-10) (16-10)

=v16x4x6x6=48cm2