the base of an isosceles triangle is 12 cm and its perimeter is 32 cm find its area
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Answered by
9
area of an isosceles triangle=1/2 × b× h
perimeter = 3 × side ( also height)
32 cm = 3× h
32/3 = h
10.7 cm = h
now area = 1/2×12×10.7
= 64.2 cm²
perimeter = 3 × side ( also height)
32 cm = 3× h
32/3 = h
10.7 cm = h
now area = 1/2×12×10.7
= 64.2 cm²
Answered by
3
Base=12cm
perimeter=32cm
let equal side be x
x+x+12=32
2x=20
x=10cm
ok
now
semiperimeter (s)=16cm
area=√s(s-a)(s-b)(s-c)
area=√16(4)(10)(10)
area=80cm^2
so area of triangle is 80cm^2
perimeter=32cm
let equal side be x
x+x+12=32
2x=20
x=10cm
ok
now
semiperimeter (s)=16cm
area=√s(s-a)(s-b)(s-c)
area=√16(4)(10)(10)
area=80cm^2
so area of triangle is 80cm^2
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