the base of an isosceles triangle is 12 cm and its perimeter is 32 cm find its area
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given:
base =12 cm
to find side a and b=
perimeter=12+2x. (isoceles triangle have two equal sides.)
32=12+2x
32-12=2x
20=2x
20/2=X
10=x.
now , to find area ..
s=p/2=32/2=16 cm.
by using Heron's formula,
area =√s(s-a)(s-b)(s-c)
=√16(16-10)(16-10)(16-12)
=√16(6)(6)(4)
=√4*4*6*6*4
=√2*2*2*2*3*2*3*2*2*2
=2*2*2*2*3
=48cm^2
therefore the area of the isoceles triangle is 48cm^2.
hope it helps u mate....
pls mark me brainliest
base =12 cm
to find side a and b=
perimeter=12+2x. (isoceles triangle have two equal sides.)
32=12+2x
32-12=2x
20=2x
20/2=X
10=x.
now , to find area ..
s=p/2=32/2=16 cm.
by using Heron's formula,
area =√s(s-a)(s-b)(s-c)
=√16(16-10)(16-10)(16-12)
=√16(6)(6)(4)
=√4*4*6*6*4
=√2*2*2*2*3*2*3*2*2*2
=2*2*2*2*3
=48cm^2
therefore the area of the isoceles triangle is 48cm^2.
hope it helps u mate....
pls mark me brainliest
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