The Base of an isosceles triangle is 12cm and it's perimeter is 32cm.Find it's area.
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its area is
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48 sq cm
Let the congruent sides of the isosceles triangle =a and the base =b.
Given, b=12cm
Perimeter of the triangle =Sum of all sides = a + a + b =32
⇒2a+12=32
On solving, a =10cm
Since the height of the triangle, divides it into two right angled triangles,
a
2
=h
2
+(
2
b
)
2
⇒10
2
=h
2
+6
2
h
2
=100−36=64
h=
64
=8 cm
Area of triangle =
2
1
×base×height=
2
1
×12×8=48 sq cm
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