The base of an isosceles triangle is 12cm and its perimeter is 32cm.find its area
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let x be the side
perimeter of an isosceles triangle= base+2×side
12+2x=32
2x=20
x=10
the sides are of 10 cm each
perimeter of an isosceles triangle= base+2×side
12+2x=32
2x=20
x=10
the sides are of 10 cm each
Answered by
0
perimeter=32cm
isosceles triangle = 1x + 2x
isosceles triangle= 12 cm
32-12=22cm
22cm÷2= 11 cm
Ans)) The both two sides will measure same that is 11 cm
isosceles triangle = 1x + 2x
isosceles triangle= 12 cm
32-12=22cm
22cm÷2= 11 cm
Ans)) The both two sides will measure same that is 11 cm
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