the base of an isosceles triangle is 12cm and its perimeter is 32cm find its area
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Hey MATE!
An isosceles triangle has 2 sides equal, therefore in ΔABC,
AB = AC = 12cm
perimeter = Sum of all sides = 32 cm
Let the 3rd unknown side be x cm.
Therefore,
12 + 12 + x = 32
24 + x = 32
x = 32 - 24
x = 8 cm
Area of Δ = √{s(s-a) (s-b) (s-c)}
Semi perimeter = s = 32/2 = 16cm
Area = √{16(16-12)(16-12)(16-8)}
=> √{16 × 4 × 4 × 8}
=> √{4 × 4 × 4 × 4 × 2 × 2 ×2 }
=> 4*4*2 √2
=> 32√2 cm² Answer
Hope it helps
Hakuna Matata :))
An isosceles triangle has 2 sides equal, therefore in ΔABC,
AB = AC = 12cm
perimeter = Sum of all sides = 32 cm
Let the 3rd unknown side be x cm.
Therefore,
12 + 12 + x = 32
24 + x = 32
x = 32 - 24
x = 8 cm
Area of Δ = √{s(s-a) (s-b) (s-c)}
Semi perimeter = s = 32/2 = 16cm
Area = √{16(16-12)(16-12)(16-8)}
=> √{16 × 4 × 4 × 8}
=> √{4 × 4 × 4 × 4 × 2 × 2 ×2 }
=> 4*4*2 √2
=> 32√2 cm² Answer
Hope it helps
Hakuna Matata :))
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