the base of an isosceles triangle is 16 cm and its radius 40 cm square find the perimeter of a triangle
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Area of a triangle = 1/2 (base)(height)
A(t) = 0.5 (16)(h) = 48
h = 48 / (0.5)(16) = 6 cm
The triangle can be considered as 2 triangles with
base 16/2 and height 6
the 3rd side of these triangles is (8^2 + 6^2)^(1/2) = (64+36)^0.5 = 10
Perimeter of original triangle is 10+10+16 = 36 cm.
A(t) = 0.5 (16)(h) = 48
h = 48 / (0.5)(16) = 6 cm
The triangle can be considered as 2 triangles with
base 16/2 and height 6
the 3rd side of these triangles is (8^2 + 6^2)^(1/2) = (64+36)^0.5 = 10
Perimeter of original triangle is 10+10+16 = 36 cm.
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