the base of an isosceles triangle is 16cm and its area is 48 cm find its perimeter
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Answered by
1
Answer:
36 cm
Step-by-step explanation:
Area = 1/2 × Base × Height
Given that,
Area = 48 cm²
Base = 16 cm
=> 48 = 1/2 × 16 × Height
=> Height = 48/8
=> Height = 6 cm
Hence, other side = √(8²+6²) = √(64+36) = √100 = 10 cm
Therefore, perimeter of triangle = (10+10+16) cm = 36 cm
Answered by
0
Answer:
let h is the height of the triangle
so, 1/2 ×base×height=48
1/2×16×height=48
height=48×2/16=3×2=6
height =6cm
half of the base =16/2cm=8cm
according to Pythagoras theorem,the same two side of the triangle is
√(height^2+half of the base^2)
=√(36+64)
=√100
=10
so the perimeter of the triangle is (10+10+16)cm=36cm
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