Question

The base of an isosceles triangle is 24 cm and its area is
60 cm2. Find its perimeter.

Answer 1

Answer:

Let the the triangle be ABC in which D is mid-point of AC

AC=24 , therefore AD=12cm

Area =60cm

2

and we know that area of triangle =

2

1

×AC×BD

then, 60=

2

1

×24×BD

BD=5cm

Now, by Pythagoras theorem

AB

2

=AD

2

+BD

2

AB=13

Now perimeter of ΔABC=AB+BC+AC=2AB+AC (two sides of isosceles triangle are equal)

Perimeter =26+24=50cm

Step-by-step explanation:

hope it helps